f(-3)=2-3^(2)-6-3+3

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Solution for f(-3)=2-3^(2)-6-3+3 equation: 



f(-3)=2-3^(2)-6-3+3

We move all terms to the left:

f(-3)-(2-3^(2)-6-3+3)=0

We add all the numbers together, and all the variables

f(-3)+13=0

We multiply parentheses

-3f+13=0

We move all terms containing f to the left, all other terms to the right

-3f=-13

f=-13/-3

f=4+1/3

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